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Ohm's Law

02468AMPERES2.00 AVARIABLE RESISTOR · 3.0 Ω6.0 VDC POWER SUPPLY−+Steady currentA balanced circuit6.0 V ÷ 3.0 Ω = 2.00 Aelectron flow
Ohm’s law
I=VR=63=2 AI = \frac{V}{R} = \frac{6}{3} = 2\,\text{A}
Current through circuit2.00 A
Potential difference6.0 V
Resistance3.0 Ω
Power dissipated12.00 W
Try a circuit setup

Increase voltage to push more charge each second. Increase resistance to oppose that flow. The moving dots represent electrons, so they travel from the negative terminal toward the positive terminal—opposite to conventional current. This model assumes an ideal ohmic resistor at constant temperature.

  • Make the current read exactly 2.00 A
  • Bring the current below 0.50 A
  • Reach exactly 4.00 A
  • Get 1.50 A with the resistance set to 8 Ω (what voltage does that need?)